LeetCode 2625: Flatten Deeply Nested Array Solution
Master LeetCode problem 2625 (Flatten Deeply Nested Array), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2625. Flatten Deeply Nested Array
Problem Explanation
Explanation:
To flatten a deeply nested array up to a certain depth n, we can use a recursive approach. We iterate through the elements of the array, and if an element is an array and the current depth is less than n, we recursively flatten that sub-array. If the depth reaches n, we simply add the element as is to the flattened array.
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Algorithm:
- Initialize an empty list to store the flattened array.
- Iterate through each element in the input array:
- If the element is an array and the current depth < n, recursively flatten the sub-array with depth + 1.
- Otherwise, add the element to the flattened array.
- Return the flattened array.
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Time Complexity: O(N), where N is the total number of elements in the input array.
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Space Complexity: O(N), for the recursive call stack.
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Solution Code
class Solution {
public List<Object> flattenArray(Object[] arr, int n) {
List<Object> flattened = new ArrayList<>();
for (Object element : arr) {
if (element instanceof Object[] && n > 0) {
flattened.addAll(flattenArray((Object[]) element, n - 1));
} else {
flattened.add(element);
}
}
return flattened;
}
}Try It Yourself
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