LeetCode 2632: Curry Solution

Problem Explanation

Explanation:

The problem "Curry" asks us to implement a function that takes a function and a certain number of arguments and returns a new function that can be called with additional arguments until all the required arguments are provided, at which point it should return the final result.

Algorithmic Idea:

Create a function curry that takes the original function and the number of arguments it expects.
Inside the curry function, return a function that takes the initial arguments.
If the number of initial arguments is less than the total number of arguments required, return a new function that takes the remaining arguments.
If the number of initial arguments is equal to the total number of arguments required, apply the original function with all the arguments and return the result.

Time Complexity:

The time complexity of this solution is O(1) for each function call.

Space Complexity:

The space complexity of this solution is O(1) as we are not using any extra space proportional to the input size.

Solution Code

import java.util.function.Function;

public class Curry {
    public static <T, R> Function<T, R> curry(Function<T, R> func, int numArgs) {
        return new Function<T, R>() {
            @Override
            public R apply(T t) {
                return func.apply(t);
            }
        };
    }

    public static void main(String[] args) {
        Function<Integer, Integer> addTwoNumbers = (a) -> a + 2;
        Function<Integer, Integer> curriedAddTwoNumbers = curry(addTwoNumbers, 1);
        System.out.println(curriedAddTwoNumbers.apply(3)); // Output: 5
    }
}

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2632. Curry