DevExCode

2656. Maximum Sum With Exactly K Elements

ArrayGreedy

Explanation

To maximize the score, we should always choose the largest element from the array since it gives us the highest score. We can achieve this by sorting the array in descending order and then selecting the first k elements to perform the operation on.

Here's the step-by-step approach:

  1. Sort the input array nums in descending order.
  2. Iterate through the first k elements of the sorted array.
  3. For each element, calculate the new value after the operation (element + 1) and add it to the total score.
  4. Return the total score as the maximum score achievable.

Time complexity: O(n log n) where n is the length of the input array nums due to sorting. Space complexity: O(1) since we are not using any extra space.

View Leetcode Problem
import java.util.Arrays;

class Solution {
    public int maxScore(int[] nums, int k) {
        Arrays.sort(nums);
        int n = nums.length;
        int score = 0;

        for (int i = n - 1; i >= n - k; i--) {
            score += nums[i];
        }

        return score + k;
    }
}

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