LeetCode 2680: Maximum OR Solution

Master LeetCode problem 2680 (Maximum OR), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2680. Maximum OR

Medium

Array Greedy Bit Manipulation Prefix Sum

Problem Explanation

Explanation

To solve this problem, we need to find the maximum possible value of the bitwise OR operation applied to the elements of the array after applying the multiplication operation at most k times. We can achieve this by iteratively selecting the element with the highest bit set at the position we are interested in increasing.

The algorithm involves finding the leftmost set bit in each element of the array. We then iterate over k times, each time selecting the element that has the highest leftmost set bit. We double that element by multiplying it by 2 and update the leftmost set bit position. Finally, we calculate the bitwise OR of all elements to get the maximum possible value.

Time complexity: O(nk) where n is the length of the array and k is the maximum number of operations allowed.
Space complexity: O(1)

Solution Code

class Solution {
    public int maximumOr(int[] nums, int k) {
        int res = 0;
        for (int i = 30; i >= 0; i--) {
            int mask = 1 << i;
            int count = 0;
            for (int num : nums) {
                if ((num & mask) == mask) {
                    count++;
                }
            }
            if (count > 0) {
                if (k > 0) {
                    int maxCount = Math.min(count, k);
                    res |= mask;
                    k -= maxCount;
                } else {
                    res |= mask;
                }
            }
        }
        return res;
    }
}

Try It Yourself

Loading code editor...

Frequently Asked Questions

How to solve LeetCode 2680 (Maximum OR)?

This page provides optimized solutions for LeetCode problem 2680 (Maximum OR) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.

What is the time complexity of LeetCode 2680 (Maximum OR)?

The time complexity for LeetCode 2680 (Maximum OR) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

Can I run code for LeetCode 2680 on DevExCode?

Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 2680 in Java, C++, or Python.

Back to LeetCode Solutions