LeetCode 2683: Neighboring Bitwise XOR Solution
Master LeetCode problem 2683 (Neighboring Bitwise XOR), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2683. Neighboring Bitwise XOR
Problem Explanation
Explanation
To solve this problem, we need to find a valid original array that could have formed the given derived array by computing the bitwise XOR of adjacent elements. We can observe that for each index i, the derived value at index i is the result of XOR operation between original values at index i and i+1 (or 0 if i = n-1).
We can start by iterating through the derived array and check if we can construct the original array based on the XOR property. If we encounter any inconsistency during this process, we return false. Otherwise, we return true.
The time complexity of this approach is O(n) where n is the length of the derived array. The space complexity is O(1) as we are not using any extra space apart from a few variables.
Solution Code
class Solution {
public boolean validateBinaryArray(int[] derived) {
int n = derived.length;
for (int i = 0; i < n; i++) {
if (derived[i] != (i == n - 1 ? derived[i] ^ derived[0] : derived[i] ^ derived[i + 1])) {
return false;
}
}
return true;
}
}Try It Yourself
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