LeetCode 2704: To Be Or Not To Be Solution

Master LeetCode problem 2704 (To Be Or Not To Be), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2704. To Be Or Not To Be

Easy

Problem Explanation

Explanation

To implement the expect function, we can create an object that stores the initial value and provides two methods toBe and notToBe to check equality and inequality with other values respectively. We can use these methods to compare the initial value with the passed value and throw errors if the conditions are not met.

Time Complexity

The time complexity for each operation (toBe and notToBe) is O(1) as we are performing simple equality and inequality checks.

Space Complexity

The space complexity is O(1) as we are not using any extra space that grows with the input size.

Solution Code

class Expect {
    private Object value;

    public Expect(Object value) {
        this.value = value;
    }

    public boolean toBe(Object other) {
        if (this.value.equals(other)) {
            return true;
        } else {
            throw new RuntimeException("Not Equal");
        }
    }

    public boolean notToBe(Object other) {
        if (!this.value.equals(other)) {
            return true;
        } else {
            throw new RuntimeException("Equal");
        }
    }
}

class Main {
    public static Expect expect(Object value) {
        return new Expect(value);
    }
}

Try It Yourself

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What is the time complexity of LeetCode 2704 (To Be Or Not To Be)?

The time complexity for LeetCode 2704 (To Be Or Not To Be) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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