LeetCode 2713: Maximum Strictly Increasing Cells in a Matrix Solution
Master LeetCode problem 2713 (Maximum Strictly Increasing Cells in a Matrix), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2713. Maximum Strictly Increasing Cells in a Matrix
Problem Explanation
Explanation
To solve this problem, we can use a dynamic programming approach. We can iterate over each cell in the matrix and calculate the maximum number of cells that can be visited starting from that cell. We can keep track of these counts in a separate matrix. For each cell, we check its neighbors to see if we can move to a cell with a strictly greater value. If we can move to a neighbor cell, we update the count for the current cell by adding 1 to the count of the neighbor cell.
Finally, we find the maximum count in the entire matrix, which represents the maximum number of cells that can be visited by starting from any cell.
- Time complexity: O(mn) where m is the number of rows and n is the number of columns in the matrix.
- Space complexity: O(mn) to store the count matrix.
Solution Code
class Solution {
public int maxCells(int[][] mat) {
int m = mat.length;
int n = mat[0].length;
int[][] dp = new int[m][n];
int maxCells = 0;
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
dp[i][j] = 1;
if (i > 0 && mat[i][j] > mat[i - 1][j]) {
dp[i][j] = Math.max(dp[i][j], dp[i - 1][j] + 1);
}
if (j > 0 && mat[i][j] > mat[i][j - 1]) {
dp[i][j] = Math.max(dp[i][j], dp[i][j - 1] + 1);
}
maxCells = Math.max(maxCells, dp[i][j]);
}
}
return maxCells;
}
}Try It Yourself
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