LeetCode 2740: Find the Value of the Partition Solution

Master LeetCode problem 2740 (Find the Value of the Partition), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2740. Find the Value of the Partition

Medium

Array Sorting

Problem Explanation

Explanation:

To find the value of the partition, we need to split the given array into two non-empty arrays in such a way that the absolute difference between the maximum of one array and the minimum of the other array is minimized.

We can achieve this by sorting the input array and then trying all possible splits to find the minimum absolute difference.

Sort the input array nums.
Initialize two pointers left and right at the start and end of the array.
Calculate the absolute difference between nums[left] and nums[right].
Move the pointer with the smaller value towards the center.
Repeat step 3 and 4 until the pointers meet.
Return the minimum absolute difference found.

The time complexity of this approach is O(n log n) due to the sorting step, and the space complexity is O(1) since we are not using any extra space.

Solution Code

class Solution {
    public int findValueOfThePartition(int[] nums) {
        Arrays.sort(nums);
        int left = 0, right = nums.length - 1;
        int minDiff = Integer.MAX_VALUE;

        while (left < right) {
            minDiff = Math.min(minDiff, Math.abs(nums[left] - nums[right]));
            if (nums[left] < nums[right]) {
                left++;
            } else {
                right--;
            }
        }

        return minDiff;
    }
}

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