LeetCode 2750: Ways to Split Array Into Good Subarrays Solution

Master LeetCode problem 2750 (Ways to Split Array Into Good Subarrays), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2750. Ways to Split Array Into Good Subarrays

Medium

Array Math Dynamic Programming

Problem Explanation

Explanation:

To solve this problem, we can iterate over the binary array nums and keep track of the indices of the 1's in the array. For each 1 encountered, we can calculate the number of good subarrays that end at that index. The total number of ways to split the array into good subarrays is the sum of these individual counts.

We can use two pointers to efficiently find the number of good subarrays ending at each 1. We can iterate from left to right and maintain a sliding window that ensures exactly one 1 within the window. By counting the number of zeros before the 1 and the number of zeros after the 1, we can calculate the number of ways to split the array at that point. Solution:

Solution Code

class Solution {
    public int numWays(int[] nums) {
        int n = nums.length;
        int mod = 1000000007;
        long ans = 0;
        List<Integer> ones = new ArrayList<>();
        
        for (int i = 0; i < n; i++) {
            if (nums[i] == 1) ones.add(i);
        }
        
        int countOnes = ones.size();
        
        if (countOnes < 2) return 0;
        
        for (int i = 1; i < countOnes; i++) {
            int leftZeros = ones.get(i) - ones.get(i - 1);
            int rightZeros = n - ones.get(i);
            ans = (ans + (long) leftZeros * rightZeros) % mod;
        }
        
        return (int) ans;
    }
}

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