LeetCode 2753: Count Houses in a Circular Street II Solution

Master LeetCode problem 2753 (Count Houses in a Circular Street II), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2753. Count Houses in a Circular Street II

Hard

Problem Explanation

Explanation

To solve this problem, we can iterate through each house and for each house, we calculate the distance to its nearest neighbor on the right and on the left. We then find the minimum of these two distances to determine the minimum distance to the nearest neighbor for each house. Finally, we count the number of houses that have a minimum distance greater than or equal to a given threshold.

Start by calculating the distances from each house to its neighbors
Find the minimum distance on the right and left for each house
Count the number of houses with a minimum distance greater than or equal to the threshold

Time complexity: O(n) where n is the number of houses Space complexity: O(n) for storing the distances

Solution Code

class Solution {
    public int countHouses(int[] houses, int threshold) {
        int n = houses.length;
        int count = 0;
        
        for (int i = 0; i < n; i++) {
            int minDist = Integer.MAX_VALUE;
            
            for (int j = 0; j < n; j++) {
                if (i != j) {
                    int dist = Math.min(Math.abs(houses[i] - houses[j]), n - Math.abs(houses[i] - houses[j]));
                    minDist = Math.min(minDist, dist);
                }
            }
            
            if (minDist >= threshold) {
                count++;
            }
        }
        
        return count;
    }
}

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