LeetCode 2758: Next Day Solution

Master LeetCode problem 2758 (Next Day), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2758. Next Day

Easy

Problem Explanation

Explanation

To solve this problem, we need to implement a function that takes a date in the format "YYYY-MM-DD" and returns the next day's date in the same format. We need to consider leap years while calculating the next day.

Algorithm:

Parse the input date into year, month, and day components.
Check if it is a leap year based on the year component.
Determine the number of days in the current month based on the month component.
Increment the day component by 1.
If the day component exceeds the number of days in the current month, set it to 1 and increment the month component.
If the month component exceeds 12, set it to 1 and increment the year component.
Adjust the number of days in February if it's a leap year.
Return the next day's date in the format "YYYY-MM-DD".

Time Complexity:

The time complexity of this algorithm is O(1) as we are performing a constant number of operations.

Space Complexity:

The space complexity of this algorithm is O(1) as we are using a constant amount of extra space.

Solution Code

class Solution {
    public String nextDay(String date) {
        int year = Integer.parseInt(date.substring(0, 4));
        int month = Integer.parseInt(date.substring(5, 7));
        int day = Integer.parseInt(date.substring(8));

        int[] daysInMonth = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

        if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) {
            daysInMonth[2] = 29;
        }

        day++;
        if (day > daysInMonth[month]) {
            day = 1;
            month++;
        }
        if (month > 12) {
            month = 1;
            year++;
        }

        return String.format("%04d-%02d-%02d", year, month, day);
    }
}

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