LeetCode 2775: Undefined to Null Solution
Master LeetCode problem 2775 (Undefined to Null), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2775. Undefined to Null
Problem Explanation
Explanation
To solve this problem, we need to convert any occurrence of "undefined" in a given list to "null". We can iterate through the list and replace "undefined" with "null" in place.
- Iterate through the list.
- If the current element is "undefined", replace it with "null".
Time Complexity
The time complexity of this approach is O(n), where n is the number of elements in the list.
Space Complexity
The space complexity of this approach is O(1) as we are modifying the list in place.
Solution Code
class Solution {
public void undefinedToNull(List<Object> list) {
for (int i = 0; i < list.size(); i++) {
if (list.get(i) instanceof String && ((String) list.get(i)).equals("undefined")) {
list.set(i, null);
}
}
}
}Try It Yourself
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What is the time complexity of LeetCode 2775 (Undefined to Null)?
The time complexity for LeetCode 2775 (Undefined to Null) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.
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