LeetCode 2778: Sum of Squares of Special Elements Solution
Master LeetCode problem 2778 (Sum of Squares of Special Elements ), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2778. Sum of Squares of Special Elements
Problem Explanation
Explanation:
- We need to find the sum of the squares of all special elements in the given array.
- An element is considered special if its index divides the length of the array without any remainder.
- To solve this problem, we iterate over the array and check if the index divides the length of the array.
- If the index divides the length, we square the element at that index and add it to the answer.
- Finally, we return the sum of the squares of all special elements.
Time Complexity: O(n) Space Complexity: O(1)
:
Solution Code
class Solution {
public int sumOfSquaresOfSpecialElements(int[] nums) {
int n = nums.length;
int sum = 0;
for (int i = 0; i < n; i++) {
if (n % (i + 1) == 0) {
sum += nums[i] * nums[i];
}
}
return sum;
}
}Try It Yourself
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