LeetCode 2786: Visit Array Positions to Maximize Score Solution
Master LeetCode problem 2786 (Visit Array Positions to Maximize Score), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2786. Visit Array Positions to Maximize Score
Problem Explanation
Explanation:
- Algorithmic Idea: We can solve this problem using dynamic programming. We will iterate through the array and maintain two states for each position: the maximum score if we include the current position and the maximum score if we exclude the current position. We will update these states based on the rules mentioned in the problem description.
- Step-by-Step Iterations:
- Initialize two arrays
includeandexcludeto keep track of the maximum scores at each position. - Iterate through the array and update
includeandexcludebased on the rules. - At each position, we can either include the current element (if allowed) by adding the current score to the maximum score excluding the previous element or exclude the current element by taking the maximum of the previous maximum scores.
- Return the maximum score at the last position.
- Initialize two arrays
- Time Complexity: O(n), where n is the number of elements in the input array
nums. - Space Complexity: O(n), for storing the
includeandexcludearrays.
:
Solution Code
class Solution {
public int visitArrayPositions(int[] nums, int x) {
int n = nums.length;
int[] include = new int[n];
int[] exclude = new int[n];
include[0] = nums[0];
for (int i = 1; i < n; i++) {
include[i] = Math.max(include[i - 1] + nums[i], exclude[i - 1] + nums[i]);
exclude[i] = Math.max(include[i - 1], exclude[i - 1] - x);
}
return Math.max(include[n - 1], exclude[n - 1]);
}
}Try It Yourself
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