LeetCode 2789: Largest Element in an Array after Merge Operations Solution

Master LeetCode problem 2789 (Largest Element in an Array after Merge Operations), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2789. Largest Element in an Array after Merge Operations

Medium

Array Greedy

Problem Explanation

Explanation

To solve this problem, we need to find the largest element that can be obtained by applying the given operation on the array any number of times. The key idea is to iteratively merge adjacent elements to maximize the value of the largest element in the array.

We start by iterating through the array from left to right.
For each pair of adjacent elements where the left element is smaller or equal to the right element, we merge them by replacing the right element with the sum of the two elements.
We repeat this process until we can no longer merge any adjacent elements.
The largest element in the final array is the result we are looking for.

The time complexity of this approach is O(n) where n is the length of the input array nums. The space complexity is O(1) as we are modifying the array in place.

Solution Code

class Solution {
    public int getLargestElement(int[] nums) {
        int n = nums.length;
        for (int i = 0; i < n - 1; i++) {
            if (nums[i] <= nums[i + 1]) {
                nums[i + 1] += nums[i];
                nums[i] = 0;
            }
        }
        int max = 0;
        for (int num : nums) {
            max = Math.max(max, num);
        }
        return max;
    }
}

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