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LeetCode 2803: Factorial Generator Solution

Master LeetCode problem 2803 (Factorial Generator), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2803. Factorial Generator

Easy

Problem Explanation

Explanation:

To generate the factorial of a given number, we can use a simple iterative approach where we start from 1 and multiply it with all integers up to the given number. This way, we calculate the factorial result.

Algorithm:

  1. Initialize a variable factorial to 1.
  2. Iterate from 1 to the given number.
  3. Multiply the current number with the factorial variable.
  4. Update the factorial variable with the result of multiplication.
  5. Return the factorial variable as the final result.

Time Complexity:

The time complexity of this algorithm is O(n) where n is the given number for which we need to calculate the factorial.

Space Complexity:

The space complexity of this algorithm is O(1) as we are using a constant amount of extra space.

:

Solution Code

class Solution {
    public int generateFactorial(int n) {
        int factorial = 1;
        for (int i = 1; i <= n; i++) {
            factorial *= i;
        }
        return factorial;
    }
}

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Frequently Asked Questions

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What is the time complexity of LeetCode 2803 (Factorial Generator)?

The time complexity for LeetCode 2803 (Factorial Generator) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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