LeetCode 2808: Minimum Seconds to Equalize a Circular Array Solution
Master LeetCode problem 2808 (Minimum Seconds to Equalize a Circular Array), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2808. Minimum Seconds to Equalize a Circular Array
Problem Explanation
Explanation:
To solve this problem, we can observe that at each second, the value at each index can be replaced by the maximum value of its neighboring elements. We need to find the minimum number of seconds needed to make all elements in the array equal.
- Initialize a variable
maxValto store the maximum element in the array. - Iterate through the array to find the maximum element.
- Check if all elements are equal to
maxVal. If they are, return 0. - Otherwise, calculate the minimum number of seconds needed by subtracting the count of elements equal to
maxValfrom the total number of elements in the array.
:
Solution Code
class Solution {
public int minSeconds(int[] nums) {
int maxVal = Integer.MIN_VALUE;
for (int num : nums) {
maxVal = Math.max(maxVal, num);
}
if (Arrays.stream(nums).allMatch(x -> x == maxVal)) {
return 0;
}
return nums.length - (int)Arrays.stream(nums).filter(x -> x == maxVal).count();
}
}Try It Yourself
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