LeetCode 2818: Apply Operations to Maximize Score Solution
Master LeetCode problem 2818 (Apply Operations to Maximize Score), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2818. Apply Operations to Maximize Score
Problem Explanation
Explanation:
To maximize the score, we need to choose subarrays intelligently. We can iterate over all possible subarrays and calculate the prime score for each element. Then, for each operation, we choose the element with the highest prime score within the remaining subarrays. We can use a priority queue to keep track of the maximum prime score element efficiently. Finally, we multiply the score by the chosen element and update the remaining subarrays accordingly.
- Time Complexity: O(n^2 * k * log(k)) where n is the length of the input array nums.
- Space Complexity: O(n)
Solution Code
import java.util.*;
class Solution {
public int maxScore(int[] nums, int k) {
int n = nums.length;
PriorityQueue<Integer> pq = new PriorityQueue<>((a, b) -> Integer.compare(getPrimeScore(b), getPrimeScore(a)));
for (int i = 0; i < n; i++) {
pq.offer(nums[i]);
}
long score = 1;
int mod = 1000000007;
for (int i = 0; i < k; i++) {
int max = pq.poll();
score = (score * max) % mod;
pq.offer(max);
}
return (int) score;
}
private int getPrimeScore(int num) {
Set<Integer> factors = new HashSet<>();
for (int i = 2; i * i <= num; i++) {
while (num % i == 0) {
factors.add(i);
num /= i;
}
}
if (num > 1) factors.add(num);
return factors.size();
}
}Try It Yourself
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