LeetCode 2822: Inversion of Object Solution
Master LeetCode problem 2822 (Inversion of Object), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2822. Inversion of Object
Problem Explanation
Explanation:
To invert an object, we need to reverse the values of the keys and values in the given object. For example, if we have { 'a': 1, 'b': 2 }, the inverted object would be { 1: 'a', 2: 'b' }.
We can achieve this by iterating over each key-value pair in the input object and swapping the key-value pairs to create the inverted object.
Algorithm:
- Create an empty inverted object.
- Iterate over each key-value pair in the input object.
- For each key-value pair, swap the key and value and add it to the inverted object.
- Return the inverted object.
Time Complexity:
The time complexity of this algorithm is O(n), where n is the number of key-value pairs in the input object.
Space Complexity:
The space complexity of this algorithm is O(n) as we need to store the inverted object.
:
Solution Code
public Map<Object, Object> invertObject(Map<Object, Object> obj) {
Map<Object, Object> invertedObj = new HashMap<>();
for (Map.Entry<Object, Object> entry : obj.entrySet()) {
invertedObj.put(entry.getValue(), entry.getKey());
}
return invertedObj;
}Try It Yourself
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