LeetCode 2826: Sorting Three Groups Solution

Master LeetCode problem 2826 (Sorting Three Groups), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2826. Sorting Three Groups

Medium

Array Binary Search Dynamic Programming

Problem Explanation

Explanation:

To solve this problem efficiently in O(n) time complexity, we can iterate through the array once and count the number of occurrences of each value (1, 2, 3). Then, we can calculate the minimum number of removals needed by considering the possible scenarios for each group of numbers.

Here is the step-by-step approach:

Count the occurrences of each value in the array.
Calculate the total number of elements that need to be removed to make each group non-decreasing.
Return the minimum number of removals needed.

Time complexity: O(n) Space complexity: O(1)

Solution Code

public int minOperations(int[] nums) {
    int count1 = 0, count2 = 0, count3 = 0;
    
    for (int num : nums) {
        if (num == 1) count1++;
        else if (num == 2) count2++;
        else count3++;
    }
    
    int operations1 = nums.length - count1 - count2;
    int operations2 = count1 + count3;
    int operations3 = Math.max(count1, count3);
    
    return Math.min(operations1, Math.min(operations2, operations3));
}

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