LeetCode 2827: Number of Beautiful Integers in the Range Solution

Master LeetCode problem 2827 (Number of Beautiful Integers in the Range), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2827. Number of Beautiful Integers in the Range

Hard

Math Dynamic Programming

Problem Explanation

Explanation

To solve this problem, we can iterate through all numbers in the range [low, high] and check if each number is beautiful according to the given conditions. We can determine if a number is beautiful by counting the even and odd digits, checking if they are equal, and verifying if the number is divisible by k.

We will implement a function to count the number of even and odd digits in a given number. Then, we iterate through all numbers in the range [low, high], apply the conditions to determine if a number is beautiful, and increment a count if it meets the criteria.

The time complexity of this solution is O((high - low) * log(high)), where log(high) represents the number of digits in the highest number in the range. The space complexity is O(1).

Solution Code

class Solution {
    public int countBeautifulNumbers(int low, int high, int k) {
        int beautifulCount = 0;
        for (int num = low; num <= high; num++) {
            if (isBeautiful(num, k)) {
                beautifulCount++;
            }
        }
        return beautifulCount;
    }
    
    private boolean isBeautiful(int num, int k) {
        int evenCount = 0, oddCount = 0;
        while (num > 0) {
            int digit = num % 10;
            if (digit % 2 == 0) {
                evenCount++;
            } else {
                oddCount++;
            }
            num /= 10;
        }
        return evenCount == oddCount && num % k == 0;
    }
}

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