LeetCode 2829: Determine the Minimum Sum of a k-avoiding Array Solution
Master LeetCode problem 2829 (Determine the Minimum Sum of a k-avoiding Array), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To determine the minimum sum of a k-avoiding array of length n, we need to construct an array of distinct positive integers such that no pair of elements sums up to k. We can approach this problem by iteratively adding the smallest possible positive integers to our array while ensuring that the sum remains minimized and the condition of being k-avoiding is met.
- First, we sort the array in ascending order to easily select the smallest positive integers to add.
- We initialize the array with the first n integers excluding k.
- We iterate over the remaining integers to choose the smallest positive integer that does not form a pair summing up to k with any existing element in the array.
The time complexity of this approach is O(n) as we iterate over the sorted array of size n, and the space complexity is O(n) to store the k-avoiding array.
Solution Code
class Solution {
public int minSumOfKAvoidingArray(int n, int k) {
int sum = 0;
int[] avoidingArray = new int[n];
Arrays.sort(avoidingArray);
for (int i = 0; i < n; i++) {
avoidingArray[i] = i + 1 == k ? i + 2 : i + 1;
sum += avoidingArray[i];
}
return sum;
}
}Try It Yourself
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