LeetCode 2835: Minimum Operations to Form Subsequence With Target Sum Solution
Master LeetCode problem 2835 (Minimum Operations to Form Subsequence With Target Sum), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2835. Minimum Operations to Form Subsequence With Target Sum
Problem Explanation
Explanation:
This problem can be solved using a dynamic programming approach. We can iterate through the array of numbers and keep track of the minimum number of operations needed to reach each possible target sum. At each step, we update the minimum operations needed for all target sums that can be achieved from the current number.
Algorithmic Idea:
- Initialize a map to store the minimum operations needed for each target sum.
- Iterate through the array of numbers.
- For each number in the array, update the map with the new target sums that can be achieved and the minimum operations needed for each target sum.
- Return the minimum operations needed to reach the final target sum.
Time Complexity:
The time complexity of this approach is O(n * log(target)), where n is the number of elements in the array.
Space Complexity:
The space complexity of this approach is O(target).
:
Solution Code
class Solution {
public int minOperations(int[] nums, int target) {
Map<Integer, Integer> dp = new HashMap<>();
dp.put(0, 0);
int max = 0;
for (int num : nums) {
Map<Integer, Integer> temp = new HashMap<>(dp);
for (int sum : dp.keySet()) {
int newSum = sum + num;
if (newSum > target) continue;
temp.put(newSum, Math.min(temp.getOrDefault(newSum, Integer.MAX_VALUE), dp.get(sum) + 1));
max = Math.max(max, newSum);
}
dp = temp;
}
return dp.containsKey(target) ? dp.get(target) : -1;
}
}Try It Yourself
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