LeetCode 2842: Count K-Subsequences of a String With Maximum Beauty Solution
Master LeetCode problem 2842 (Count K-Subsequences of a String With Maximum Beauty), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2842. Count K-Subsequences of a String With Maximum Beauty
Problem Explanation
Explanation:
To solve this problem, we can follow these steps:
- Calculate the frequency of each character in the input string
s. - Generate all possible k-subsequences of the input string.
- Calculate the beauty value for each k-subsequence.
- Find the maximum beauty value among all k-subsequences.
- Count the number of k-subsequences with the maximum beauty value.
- Return the count modulo 10^9 + 7 as the final answer.
Time complexity: O(n * 26^k) where n is the length of the input string and k is the value of k. Space complexity: O(n) to store the frequency of characters in the input string.
:
Solution Code
class Solution {
public int countkSubstrings(String s, int k) {
int mod = 1000000007;
int[] freq = new int[26];
for (char c : s.toCharArray()) {
freq[c - 'a']++;
}
int maxBeauty = 0;
for (int i = 0; i < 26; i++) {
maxBeauty = Math.max(maxBeauty, freq[i]);
}
int count = 0;
for (int i = 0; i < 26; i++) {
if (freq[i] == maxBeauty) {
count++;
}
}
long result = 1;
for (int i = 0; i < k; i++) {
result = (result * count) % mod;
}
return (int) result;
}
}Try It Yourself
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