LeetCode 2845: Count of Interesting Subarrays Solution
Master LeetCode problem 2845 (Count of Interesting Subarrays), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2845. Count of Interesting Subarrays
Problem Explanation
Explanation:
To solve this problem, we can iterate through all possible subarrays and check if each subarray is interesting based on the given conditions. We can maintain a count of indices within each subarray that satisfy the condition and then check if this count modulo modulo is equal to k.
Here are the detailed steps:
- Initialize a variable
countto keep track of the total count of interesting subarrays. - Iterate through all possible subarrays using two nested loops for the start index and end index of the subarray.
- For each subarray, iterate through the elements to count the number of indices that satisfy the condition
nums[i] % modulo == k. - Check if this count modulo
modulois equal tok. If it is, increment thecount. - Return the final
countas the result.
Time Complexity:
The time complexity of this approach is O(N^2), where N is the number of elements in the input array nums, as we are checking all possible subarrays.
Space Complexity: The space complexity is O(1) as we are not using any extra space that grows with the input size.
:
Solution Code
class Solution {
public int countInterestingSubarrays(int[] nums, int modulo, int k) {
int count = 0;
for (int i = 0; i < nums.length; i++) {
for (int j = i; j < nums.length; j++) {
int cnt = 0;
for (int idx = i; idx <= j; idx++) {
if (nums[idx] % modulo == k) {
cnt++;
}
}
if (cnt % modulo == k) {
count++;
}
}
}
return count;
}
}Try It Yourself
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