LeetCode 2851: String Transformation Solution
Master LeetCode problem 2851 (String Transformation), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2851. String Transformation
Problem Explanation
Explanation
To solve this problem, we can iterate over all possible suffix lengths l from 1 to n-1 and check if we can transform string s into string t in k operations by removing a suffix of length l and appending it at the start. We can keep track of the number of ways we can transform s into t in exactly k operations.
Algorithm
- Initialize a count variable to keep track of the number of ways to transform
sintotinkoperations. - Iterate over all possible suffix lengths
lfrom 1 ton-1. - For each suffix length
l, check if transformingsintotin exactlykoperations is possible. - If it is possible, increment the count.
- Return the count modulo 10^9 + 7.
Time Complexity
The time complexity of this algorithm is O(n) where n is the length of the input strings s and t.
Space Complexity
The space complexity of this algorithm is O(1) as we are using only a constant amount of extra space.
Solution Code
class Solution {
public int numTransforms(String s, String t, int k) {
int n = s.length();
int count = 0;
long MOD = 1000000007;
for (int l = 1; l < n; l++) {
if ((long) (n - l) * k + l >= n && checkTransform(s, t, l)) {
count++;
}
}
return count % MOD;
}
private boolean checkTransform(String s, String t, int l) {
String suffix = s.substring(s.length() - l); // Remove suffix
String newS = suffix + s.substring(0, s.length() - l); // Append suffix at the start
return newS.equals(t);
}
}Try It Yourself
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