LeetCode 2862: Maximum Element-Sum of a Complete Subset of Indices Solution

Master LeetCode problem 2862 (Maximum Element-Sum of a Complete Subset of Indices), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2862. Maximum Element-Sum of a Complete Subset of Indices

Hard

Array Math Number Theory

Problem Explanation

Explanation

To solve this problem, we can use dynamic programming. We can iterate over all pairs of elements and check if their product is a perfect square. If it is, we can update the maximum sum for the subset ending at the current element. We maintain an array to store the maximum sum for each index. Finally, we return the maximum sum found in the array.

Initialize an array dp to store the maximum sum for each index.
Iterate over all pairs of indices and update dp accordingly.
Return the maximum value in the dp array.

Time complexity: O(n^2) Space complexity: O(n)

Solution Code

class Solution {
    public int maxElementSum(int[] nums) {
        int n = nums.length;
        int[] dp = new int[n];
        int maxSum = 0;

        for (int i = 0; i < n; i++) {
            dp[i] = nums[i];
            for (int j = 0; j < i; j++) {
                if (isPerfectSquare(i+1, j+1)) {
                    dp[i] = Math.max(dp[i], dp[j] + nums[i]);
                }
            }
            maxSum = Math.max(maxSum, dp[i]);
        }

        return maxSum;
    }

    private boolean isPerfectSquare(int a, int b) {
        int product = a * b;
        int sqrt = (int) Math.sqrt(product);
        return sqrt * sqrt == product;
    }
}

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