LeetCode 2864: Maximum Odd Binary Number Solution

Master LeetCode problem 2864 (Maximum Odd Binary Number), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2864. Maximum Odd Binary Number

Easy

Math String Greedy

Problem Explanation

Explanation

To find the maximum odd binary number, we need to place all the '1's at the end of the string and the '0's before them. The order of the '0's does not matter as long as they are before the '1's.

Iterate through the input binary string and count the number of '1's.
Create a new string with the remaining length after removing the '1's from the original string and fill it with '0's.
Append the '1's at the end of the new string to get the maximum odd binary number.

Time Complexity: O(n) where n is the length of the input string. Space Complexity: O(n) where n is the length of the input string.

Solution Code

class Solution {
    public String maximumOddBinaryNumber(String s) {
        int onesCount = 0;
        StringBuilder result = new StringBuilder();
        
        for (char c : s.toCharArray()) {
            if (c == '1') {
                onesCount++;
            } else {
                result.append('0');
            }
        }
        
        result.append("1".repeat(onesCount));
        
        return result.toString();
    }
}

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