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LeetCode 2869: Minimum Operations to Collect Elements Solution

Master LeetCode problem 2869 (Minimum Operations to Collect Elements), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2869. Minimum Operations to Collect Elements

Easy
ArrayHash TableBit Manipulation

Problem Explanation

Explanation

To solve this problem, we can simulate the process of collecting elements 1 to k in order. We iterate through the given array nums and maintain a set to keep track of the elements we have collected so far. For each element in nums, if it is one of the elements we need to collect, we remove it from the set. If the set becomes empty, it means we have collected all elements from 1 to k. We keep track of the number of operations needed to achieve this.

Algorithmic Idea

  1. Initialize a set collected to keep track of the elements we have collected so far.
  2. Initialize a variable operations to count the number of operations.
  3. Iterate through the array nums:
    • If the current element is in the collected set, remove it.
    • If the set becomes empty, increment operations and clear the set.
  4. Return the final count of operations.

Time Complexity

The time complexity of this approach is O(n), where n is the number of elements in the input array nums.

Space Complexity

The space complexity is O(k) where k is the maximum value of k.

Solution Code

class Solution {
    public int minOperations(int[] nums, int k) {
        Set<Integer> collected = new HashSet<>();
        int operations = 0;
        
        for (int num : nums) {
            if (collected.contains(num)) {
                collected.remove(num);
                if (collected.isEmpty()) {
                    operations++;
                }
            }
        }
        
        return operations;
    }
}

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