LeetCode 2871: Split Array Into Maximum Number of Subarrays Solution

Master LeetCode problem 2871 (Split Array Into Maximum Number of Subarrays), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2871. Split Array Into Maximum Number of Subarrays

Medium

Array Greedy Bit Manipulation

Problem Explanation

Explanation

To solve this problem, we can iterate through the given array nums and keep track of the prefix AND of elements seen so far. At each index i, we calculate the prefix AND up to that index. If the prefix AND changes at index i, it indicates that we need to split the array at index i to minimize the sum of scores.

Algorithmic Idea:

Initialize a variable prev to store the prefix AND of elements seen so far, and a variable count to store the number of subarrays.
Iterate through the array nums:
- Calculate the prefix AND up to the current index.
- If the prefix AND changes compared to the previous element, increment the count.
Return the final count.

Time Complexity:

The time complexity of this approach is O(N), where N is the number of elements in the input array nums.

Space Complexity:

The space complexity of this approach is O(1) as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public int splitArray(int[] nums) {
        int prev = -1;
        int count = 1;

        for (int i = 0; i < nums.length; i++) {
            int curr = prev & nums[i];
            if (curr != prev) {
                count++;
            }
            prev = curr;
        }

        return count;
    }
}

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