LeetCode 2908: Minimum Sum of Mountain Triplets I
LeetCode 2908 Solution Explanation
Explanation
To solve this problem, we need to find the minimum sum of a mountain triplet in the given array nums. A mountain triplet is defined as a triplet of indices (i, j, k) where i < j < k and nums[i] < nums[j] and nums[k] < nums[j].
We can iterate through the array and for each element as the middle element of a potential mountain triplet, find the minimum sum by checking all possible left and right elements that satisfy the mountain conditions. If a valid mountain triplet is found, we update the minimum sum.
The time complexity of this approach is O(n^3) where n is the length of the input array nums, as we are checking all possible combinations. The space complexity is O(1) as we are not using any extra space.
LeetCode 2908 Solutions in Java, C++, Python
class Solution {
public int minMountainTriplets(int[] nums) {
int n = nums.length;
int minSum = Integer.MAX_VALUE;
for (int j = 1; j < n - 1; j++) {
int leftMin = Integer.MAX_VALUE;
for (int i = 0; i < j; i++) {
if (nums[i] < nums[j]) {
leftMin = Math.min(leftMin, nums[i]);
}
}
int rightMin = Integer.MAX_VALUE;
for (int k = j + 1; k < n; k++) {
if (nums[k] < nums[j]) {
rightMin = Math.min(rightMin, nums[k]);
}
}
if (leftMin != Integer.MAX_VALUE && rightMin != Integer.MAX_VALUE) {
minSum = Math.min(minSum, leftMin + nums[j] + rightMin);
}
}
return minSum == Integer.MAX_VALUE ? -1 : minSum;
}
}Interactive Code Editor for LeetCode 2908
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