LeetCode 2908: Minimum Sum of Mountain Triplets I Solution

Master LeetCode problem 2908 (Minimum Sum of Mountain Triplets I), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2908. Minimum Sum of Mountain Triplets I

Easy

Array

Problem Explanation

Explanation

To solve this problem, we need to find the minimum sum of a mountain triplet in the given array nums. A mountain triplet is defined as a triplet of indices (i, j, k) where i < j < k and nums[i] < nums[j] and nums[k] < nums[j].

We can iterate through the array and for each element as the middle element of a potential mountain triplet, find the minimum sum by checking all possible left and right elements that satisfy the mountain conditions. If a valid mountain triplet is found, we update the minimum sum.

The time complexity of this approach is O(n^3) where n is the length of the input array nums, as we are checking all possible combinations. The space complexity is O(1) as we are not using any extra space.

Solution Code

class Solution {
    public int minMountainTriplets(int[] nums) {
        int n = nums.length;
        int minSum = Integer.MAX_VALUE;

        for (int j = 1; j < n - 1; j++) {
            int leftMin = Integer.MAX_VALUE;
            for (int i = 0; i < j; i++) {
                if (nums[i] < nums[j]) {
                    leftMin = Math.min(leftMin, nums[i]);
                }
            }

            int rightMin = Integer.MAX_VALUE;
            for (int k = j + 1; k < n; k++) {
                if (nums[k] < nums[j]) {
                    rightMin = Math.min(rightMin, nums[k]);
                }
            }

            if (leftMin != Integer.MAX_VALUE && rightMin != Integer.MAX_VALUE) {
                minSum = Math.min(minSum, leftMin + nums[j] + rightMin);
            }
        }

        return minSum == Integer.MAX_VALUE ? -1 : minSum;
    }
}

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