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LeetCode 2910: Minimum Number of Groups to Create a Valid Assignment Solution

Master LeetCode problem 2910 (Minimum Number of Groups to Create a Valid Assignment), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2910. Minimum Number of Groups to Create a Valid Assignment

Medium
ArrayHash TableGreedy

Problem Explanation

Explanation:

To solve this problem, we can use a greedy approach. We will iterate through the balls and keep track of the count of each ball number. We will then sort the counts in descending order and assign the balls to boxes in a way that the difference in the number of balls in each box does not exceed one. We will keep track of the number of boxes used and return this count as the result.

Algorithm:

  1. Create a HashMap to store the count of each ball number.
  2. Iterate through the balls and update the count in the HashMap.
  3. Sort the counts of ball numbers in descending order.
  4. Initialize a variable boxes to keep track of the number of boxes used.
  5. Iterate through the sorted counts:
    • Assign the current count of balls to a new box.
    • Update the number of boxes used.
    • Decrement the count if the count is greater than 1.
  6. Return the final number of boxes used.

Time Complexity: O(n log n) where n is the number of balls.

Space Complexity: O(n) for the HashMap to store counts.

:

Solution Code

class Solution {
    public int minNumberOfFrogs(String croakOfFrogs) {
        Map<Character, Integer> count = new HashMap<>();
        int frogs = 0, maxFrogs = 0;
        for (char ch : croakOfFrogs.toCharArray()) {
            if (ch == 'c') {
                count.put('c', count.getOrDefault('c', 0) + 1);
                maxFrogs = Math.max(maxFrogs, ++frogs);
                continue;
            }

            char prev = (char) (ch - 1);
            if (count.getOrDefault(prev, 0) == 0) {
                return -1;
            }

            count.put(prev, count.get(prev) - 1);

            if (ch == 'k') {
                frogs--;
            } else {
                count.put(ch, count.getOrDefault(ch, 0) + 1);
            }
        }
        
        return frogs == 0 ? maxFrogs : -1;
    }
}

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