LeetCode 2922: Market Analysis III Solution

Master LeetCode problem 2922 (Market Analysis III), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2922. Market Analysis III

Medium

Database

Problem Explanation

Explanation:

To solve this problem, we can iterate through the given data and maintain a sliding window of size k. We will keep track of the maximum and minimum values within this window and calculate the difference between them. At each step, we update the window and compare the new difference with the previous maximum difference to find the maximum profit possible.

Initialize variables to store the maximum profit maxProfit, the minimum value within the window minValue, and the maximum value within the window maxValue.
Iterate through the data while maintaining a sliding window of size k.
Update the minValue and maxValue within the window.
Calculate the difference between maxValue and minValue and update maxProfit if this difference is greater.
Return the maxProfit.

: :

Solution Code

class Solution {
    public int maxProfit(int[] data, int k) {
        int n = data.length;
        int maxProfit = 0;
        
        for (int i = 0; i <= n - k; i++) {
            int minValue = Integer.MAX_VALUE;
            int maxValue = Integer.MIN_VALUE;
            
            for (int j = i; j < i + k; j++) {
                minValue = Math.min(minValue, data[j]);
                maxValue = Math.max(maxValue, data[j]);
            }
            
            maxProfit = Math.max(maxProfit, maxValue - minValue);
        }
        
        return maxProfit;
    }
}

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