LeetCode 2936: Number of Equal Numbers Blocks Solution

Master LeetCode problem 2936 (Number of Equal Numbers Blocks), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2936. Number of Equal Numbers Blocks

Medium

Array Binary Search Interactive

Problem Explanation

Explanation

To solve this problem, we need to count the number of blocks in an array where all numbers within a block are equal. We can achieve this by iterating through the array and comparing each element with its adjacent element to identify blocks of equal numbers.

Algorithm:

Initialize a counter variable to 0 to store the count of equal number blocks.
Iterate through the array from index 1 to n-1.
For each element, compare it with the previous element.
If they are equal, continue checking the next element.
If they are not equal, increment the counter by 1 to indicate the end of the current block and start a new block.
After iterating through the array, the final count will be the number of equal number blocks.

Time Complexity: O(n) Space Complexity: O(1)

Solution Code

public int countBlocks(int[] nums) {
    if (nums == null || nums.length == 0) {
        return 0;
    }
    
    int count = 1;
    for (int i = 1; i < nums.length; i++) {
        if (nums[i] != nums[i - 1]) {
            count++;
        }
    }
    
    return count;
}

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Frequently Asked Questions

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What is the time complexity of LeetCode 2936 (Number of Equal Numbers Blocks)?

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