LeetCode 2950: Number of Divisible Substrings Solution

Master LeetCode problem 2950 (Number of Divisible Substrings), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2950. Number of Divisible Substrings

Problem Explanation

Explanation:

To solve this problem, we can iterate through all substrings of the input string and check if each substring is divisible by the total length of the substring. If a substring is divisible, we increment a counter by 1. Finally, we return the count of such substrings.

Algorithm:

  1. Initialize a counter variable to keep track of the number of divisible substrings.
  2. Iterate through all possible substrings of the input string.
  3. For each substring, check if it is divisible by the length of the substring.
  4. If it is divisible, increment the counter by 1.
  5. Return the final count of divisible substrings.

Time Complexity: O(n^2) where n is the length of the input string. Space Complexity: O(1)

:

Solution Code

class Solution {
    public int countDivisibleSubstrings(String s) {
        int count = 0;
        for (int i = 0; i < s.length(); i++) {
            for (int j = i + 1; j <= s.length(); j++) {
                String substr = s.substring(i, j);
                if (Integer.parseInt(substr) % substr.length() == 0) {
                    count++;
                }
            }
        }
        return count;
    }
}

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