LeetCode 2961: Double Modular Exponentiation Solution

Master LeetCode problem 2961 (Double Modular Exponentiation), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2961. Double Modular Exponentiation

Medium

Array Math Simulation

Problem Explanation

Explanation

To solve this problem, we need to iterate through the given array of variables and check if the condition ((a * b mod 10) * c) mod m equals the target value. If the condition is met, then the index is considered good. We will return an array containing the indices of all the good variables.

Algorithm:

Initialize an empty list to store the good indices.
Iterate through each variable in the input array.
Calculate the value using the formula and check if it equals the target.
If the condition is met, add the index to the list of good indices.
Return the list of good indices.

Time Complexity:

The time complexity of this algorithm is O(n), where n is the number of variables in the input array.

Space Complexity:

The space complexity of this algorithm is O(1) as we are using a constant amount of extra space regardless of the input size.

Solution Code

import java.util.ArrayList;
import java.util.List;

class Solution {
    public int[] findGoodIndices(int[][] variables, int target) {
        List<Integer> goodIndices = new ArrayList<>();
        
        for (int i = 0; i < variables.length; i++) {
            int a = variables[i][0];
            int b = variables[i][1];
            int c = variables[i][2];
            int m = variables[i][3];
            
            if (((a * b % 10) * c) % m == target) {
                goodIndices.add(i);
            }
        }
        
        return goodIndices.stream().mapToInt(Integer::intValue).toArray();
    }
}

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