LeetCode 2964: Number of Divisible Triplet Sums Solution
Master LeetCode problem 2964 (Number of Divisible Triplet Sums), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2964. Number of Divisible Triplet Sums
Problem Explanation
Explanation:
The problem asks us to find the number of triplets (a,b,c) such that 1 <= a <= b <= c <= n and a+b+c is divisible by k.
To solve this problem, we can use a hashmap to store the frequency of remainders when dividing the sum a+b+c by k. We then iterate through all possible triplets (a,b,c) and calculate the remainder when a+b+c is divided by k. For each triplet, we increment the count of valid triplets by the product of frequencies of the remainders that would make the sum divisible by k. :
Solution Code
class Solution {
public int countTriplets(int n, int k) {
int[] count = new int[k];
for (int i = 1; i <= n; i++) {
for (int j = i; j <= n; j++) {
for (int l = j; l <= n; l++) {
count[(i+j+l) % k]++;
}
}
}
int result = 0;
for (int i = 0; i < k; i++) {
result += count[i] * count[(k - i) % k] * count[(2 * k - i) % k];
}
return result;
}
}Try It Yourself
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