LeetCode 2966: Divide Array Into Arrays With Max Difference Solution

Master LeetCode problem 2966 (Divide Array Into Arrays With Max Difference), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2966. Divide Array Into Arrays With Max Difference

Medium

Array Greedy Sorting

Problem Explanation

Explanation:

To solve this problem, we can first sort the input array. Then, we can iterate over the sorted array and group elements into arrays of size 3 such that the difference between any two elements in one array is less than or equal to k. We need to ensure that we can create n/3 arrays that satisfy this condition.

Algorithm:

Sort the input array nums.
Initialize an empty 2D array result to store the divided arrays.
Iterate over the sorted nums array and group elements into arrays of size 3.
Check if the difference between any two elements in one array is less than or equal to k.
If we can create n/3 arrays that satisfy the condition, add the array to the result.
Return the result array.

Time Complexity:

The time complexity of this solution is O(n log n) due to sorting the input array.

Space Complexity:

The space complexity is O(n) for storing the sorted array and the result 2D array.

Solution Code

class Solution {
    public List<List<Integer>> divideArrayIntoArrays(int[] nums, int k) {
        Arrays.sort(nums);
        List<List<Integer>> result = new ArrayList<>();
        for (int i = 0; i < nums.length; i += 3) {
            List<Integer> subList = new ArrayList<>();
            subList.add(nums[i]);
            subList.add(nums[i + 1]);
            subList.add(nums[i + 2]);
            if (Math.abs(subList.get(0) - subList.get(1)) <= k && Math.abs(subList.get(1) - subList.get(2)) <= k) {
                result.add(subList);
            }
        }
        return result;
    }
}

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