LeetCode 2968: Apply Operations to Maximize Frequency Score Solution

Master LeetCode problem 2968 (Apply Operations to Maximize Frequency Score), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2968. Apply Operations to Maximize Frequency Score

Hard

Array Binary Search Sliding Window Sorting Prefix Sum

Problem Explanation

Explanation

To maximize the frequency score, we can approach this problem by trying to increase the frequency of the most frequent element in the array.

Algorithm:

Sort the input array nums.
Initialize variables left and right to iterate the array.
Calculate the cost to make all elements from left to right equal to nums[right].
If the cost exceeds k, move left to increase the frequency of the most frequent element.
Update the maximum frequency score while iterating.
Return the maximum frequency score.

Time Complexity: O(n log n) where n is the size of the input array nums due to sorting.

Space Complexity: O(1) as we are using constant extra space.

Solution Code

class Solution {
    public int maxFrequency(int[] nums, int k) {
        Arrays.sort(nums);
        int left = 0;
        long totalCost = 0;
        int maxFreq = 0;

        for (int right = 0; right < nums.length; right++) {
            totalCost += (long) (nums[right] - nums[right - 1]) * (right - left);
            while (totalCost > k) {
                totalCost -= nums[right] - nums[left];
                left++;
            }
            maxFreq = Math.max(maxFreq, right - left + 1);
        }

        return maxFreq;
    }
}

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