LeetCode 2972: Count the Number of Incremovable Subarrays II Solution

Master LeetCode problem 2972 (Count the Number of Incremovable Subarrays II), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2972. Count the Number of Incremovable Subarrays II

Hard

Array Two Pointers Binary Search

Problem Explanation

Explanation:

To solve this problem, we can iterate over the array and for each element, calculate the number of subarrays where that element is the maximum. This can be done by counting the number of elements to the left and right of the element that are less than or equal to it.

For each element, we calculate the total number of incremovable subarrays that can be formed with that element as the maximum. The total number of incremovable subarrays will be the sum of all these subarrays for each element in the array. :

Solution Code

class Solution {
    public int countIncremovableSubarrays(int[] nums) {
        int n = nums.length;
        long result = 0;
        
        for (int i = 0; i < n; i++) {
            int left = i;
            int right = n - i - 1;
            
            int leftCount = 1;
            while (left > 0 && nums[left - 1] <= nums[i]) {
                left--;
                leftCount++;
            }
            
            int rightCount = 1;
            while (right > 0 && nums[i] >= nums[i + right]) {
                right--;
                rightCount++;
            }
            
            result += (long) leftCount * rightCount;
        }
        
        return (int) result;
    }
}

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