LeetCode 2977: Minimum Cost to Convert String II Solution
Master LeetCode problem 2977 (Minimum Cost to Convert String II), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2977. Minimum Cost to Convert String II
Problem Explanation
Explanation
To solve this problem, we can use dynamic programming. We need to consider all possible substring combinations in the source string that can be converted to the target string. We will keep track of the minimum cost required to convert each substring to the target string.
We can iterate through all possible substrings of the source string and for each substring, we check if there is a matching conversion operation available in the given original and changed arrays. If a match is found, we update the minimum cost to convert that substring.
Finally, we return the minimum cost required to convert the entire source string to the target string.
Time Complexity: O(n^3) where n is the length of the source string. Space Complexity: O(n) for storing the minimum cost for each substring.
Solution Code
class Solution {
public int minimumConvertCost(String source, String target, String[] original, String[] changed, int[] cost) {
int n = source.length();
int[] dp = new int[n + 1];
Arrays.fill(dp, Integer.MAX_VALUE);
dp[0] = 0;
for (int i = 0; i < n; i++) {
for (int j = i + 1; j <= n; j++) {
String sub = source.substring(i, j);
for (int k = 0; k < original.length; k++) {
if (sub.equals(original[k])) {
int newCost = dp[i] + cost[k];
dp[j] = Math.min(dp[j], newCost);
}
}
}
}
return dp[n] == Integer.MAX_VALUE ? -1 : dp[n];
}
}Try It Yourself
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