LeetCode 2999: Count the Number of Powerful Integers Solution

Master LeetCode problem 2999 (Count the Number of Powerful Integers), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2999. Count the Number of Powerful Integers

Hard

Math String Dynamic Programming

Problem Explanation

Explanation:

To solve this problem, we need to iterate through all numbers in the range [start, finish] and check if each number is a powerful integer according to the given conditions.

We will iterate through all numbers from start to finish.
For each number, we will check if it ends with the suffix s and if all its digits are less than or equal to the limit.
If a number satisfies both conditions, we increment the count of powerful integers.
Finally, we return the total count of powerful integers found in the range.

Time Complexity: O((finish - start) * s.length)
Space Complexity: O(1)

Solution Code

class Solution {
    public int countPowerfulIntegers(int start, int finish, int limit, String s) {
        int count = 0;
        
        for (int i = start; i <= finish; i++) {
            if (isPowerful(i, limit, s)) {
                count++;
            }
        }
        
        return count;
    }
    
    private boolean isPowerful(int num, int limit, String s) {
        String numStr = String.valueOf(num);
        
        if (!numStr.endsWith(s)) {
            return false;
        }
        
        for (char c : numStr.toCharArray()) {
            if (Character.getNumericValue(c) > limit) {
                return false;
            }
        }
        
        return true;
    }
}

Try It Yourself

Loading code editor...

Frequently Asked Questions

How to solve LeetCode 2999 (Count the Number of Powerful Integers)?

This page provides optimized solutions for LeetCode problem 2999 (Count the Number of Powerful Integers) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.

What is the time complexity of LeetCode 2999 (Count the Number of Powerful Integers)?

The time complexity for LeetCode 2999 (Count the Number of Powerful Integers) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

Can I run code for LeetCode 2999 on DevExCode?

Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 2999 in Java, C++, or Python.

Back to LeetCode Solutions