LeetCode 3004: Maximum Subtree of the Same Color Solution
Master LeetCode problem 3004 (Maximum Subtree of the Same Color), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3004. Maximum Subtree of the Same Color
Problem Explanation
Explanation:
To solve this problem, we can perform a depth-first search (DFS) traversal of the tree. At each node, we recursively calculate the size of the maximum subtree of the same color as the current node. We keep track of the count of nodes with the same color in the subtree rooted at the current node.
We define a helper function dfs that returns a pair of values: the count of nodes with the same color in the subtree rooted at the current node and the size of the maximum same-colored subtree rooted at the current node. We update the maximum subtree size if the current subtree size is larger.
Time Complexity:
The time complexity of this solution is O(N), where N is the number of nodes in the tree.
Space Complexity:
The space complexity of this solution is O(N) due to the recursive stack space.
:
Solution Code
class TreeNode {
int val;
String color;
TreeNode left, right;
TreeNode(int val, String color) {
this.val = val;
this.color = color;
}
}
class Solution {
int maxSubtreeSize = 0;
public int largestSubtree(TreeNode root) {
if (root == null) {
return 0;
}
dfs(root);
return maxSubtreeSize;
}
private int[] dfs(TreeNode node) {
if (node == null) {
return new int[]{0, 0};
}
int[] left = dfs(node.left);
int[] right = dfs(node.right);
int count = 1 + left[0] + right[0];
int size = count;
if ((node.left == null || node.left.color.equals(node.color)) &&
(node.right == null || node.right.color.equals(node.color))) {
size = count; // Current node can be part of the subtree
maxSubtreeSize = Math.max(maxSubtreeSize, size);
}
return new int[]{count, size};
}
}Try It Yourself
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