LeetCode 3026: Maximum Good Subarray Sum Solution
Master LeetCode problem 3026 (Maximum Good Subarray Sum), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3026. Maximum Good Subarray Sum
Problem Explanation
Explanation
To solve this problem, we can iterate over the array and maintain a map/dictionary that stores the maximum sum ending at each element with the absolute difference of k. We update this map as we iterate through the array. At each element, we check if there is a valid previous element that forms a good subarray with the current element. If yes, we update the maximum sum ending at the current element. Finally, we return the maximum sum from the map/dictionary.
- Time complexity: O(n) where n is the length of the input array
nums. - Space complexity: O(n) to store the map/dictionary.
Solution Code
import java.util.*;
class Solution {
public int maxGoodSubarraySum(int[] nums, int k) {
Map<Integer, Integer> map = new HashMap<>();
map.put(0, 0);
int maxSum = 0;
int currSum = 0;
for (int num : nums) {
currSum += num;
if (map.containsKey(currSum - k)) {
maxSum = Math.max(maxSum, currSum - map.get(currSum - k));
}
map.put(currSum, Math.max(currSum, map.getOrDefault(currSum, 0)));
}
return maxSum;
}
}Try It Yourself
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