LeetCode 3029: Minimum Time to Revert Word to Initial State I Solution
Master LeetCode problem 3029 (Minimum Time to Revert Word to Initial State I), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3029. Minimum Time to Revert Word to Initial State I
Problem Explanation
Explanation:
The problem can be solved by simulating the process of removing and adding characters to the string word. We can keep track of the current state of word and after each second, we remove the first k characters and add any k characters to the end. We continue this process until word reverts to its initial state.
To find the minimum time required, we can iterate through the possible durations from 1 to word.length() and check if word reverts to its initial state within that duration. The minimum time will be the first duration where word reverts to its initial state.
Time Complexity:
The time complexity of this solution is O(n^2) where n is the length of the word. This is because for each possible duration, we perform removal and addition operations on the word.
Space Complexity:
The space complexity of this solution is O(n) where n is the length of the word. This is because we are storing the modified versions of the word in each iteration.
:
Solution Code
class Solution {
public int minTimeToType(String word, int k) {
for (int time = 1; time <= word.length(); time++) {
StringBuilder sb = new StringBuilder(word);
int i = 0;
while (i < word.length()) {
if (sb.substring(0, k).equals(word.substring(i, i + k))) {
sb.delete(0, k);
i += k;
} else {
break;
}
}
if (sb.length() == 0) {
return time;
}
word = word.substring(k) + word.substring(0, k);
}
return -1;
}
}Try It Yourself
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What is the time complexity of LeetCode 3029 (Minimum Time to Revert Word to Initial State I)?
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