LeetCode 3035: Maximum Palindromes After Operations Solution

Master LeetCode problem 3035 (Maximum Palindromes After Operations), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3035. Maximum Palindromes After Operations

Medium

Array Hash Table String Greedy Sorting Counting

Problem Explanation

Explanation:

To solve this problem, we can construct palindrome strings by swapping characters between different words. The key insight is that we can only create palindromes if the characters occur in pairs. Therefore, we need to focus on creating pairs of characters.

Count the frequency of characters in each word.
For each character, pair up as many characters as possible to form palindromes.
After pairing up all possible characters, if there are any unpaired characters, we can use them to form a single character palindrome.

Time Complexity: O(n * m) where n is the number of words and m is the maximum length of a word. Space Complexity: O(m) where m is the maximum length of a word.

Solution Code

class Solution {
    public int maxPalindromes(String[] words) {
        int n = words.length;
        int[] freq = new int[26]; // array to store character frequencies
        
        for (String word : words) {
            for (char c : word.toCharArray()) {
                freq[c - 'a']++;
            }
        }
        
        int pairs = 0;
        int singles = 0;
        
        for (int f : freq) {
            pairs += f / 2;
            singles += f % 2;
        }
        
        return Math.min(n, pairs) + (singles > 0 ? 1 : 0);
    }
}

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