LeetCode 3036: Number of Subarrays That Match a Pattern II Solution

Master LeetCode problem 3036 (Number of Subarrays That Match a Pattern II), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3036. Number of Subarrays That Match a Pattern II

Hard

Array Rolling Hash String Matching Hash Function

Problem Explanation

Explanation:

To solve this problem, we can iterate over the array nums and for each starting index i, check if the subarray starting at i matches the given pattern. We can compare the elements based on the pattern conditions, incrementing a count whenever we find a matching subarray.

Initialize a variable count to keep track of the number of subarrays that match the pattern.
Iterate over the array nums up to n - m, where m is the size of the pattern.
For each starting index i, check if the subarray starting at i matches the pattern by comparing elements based on the pattern conditions.
Increment count whenever a matching subarray is found.
Return the final count as the result.

Time Complexity: O(n) where n is the size of the array nums. We iterate through the array once.

Space Complexity: O(1) as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public int numOfSubarrays(int[] nums, int[] pattern) {
        int n = nums.length;
        int m = pattern.length;
        int count = 0;

        for (int i = 0; i <= n - m; i++) {
            boolean isMatch = true;
            for (int j = 0; j < m; j++) {
                if (pattern[j] == 1 && nums[i + j + 1] <= nums[i + j]) {
                    isMatch = false;
                    break;
                }
                if (pattern[j] == 0 && nums[i + j + 1] != nums[i + j]) {
                    isMatch = false;
                    break;
                }
                if (pattern[j] == -1 && nums[i + j + 1] >= nums[i + j]) {
                    isMatch = false;
                    break;
                }
            }
            if (isMatch) {
                count++;
            }
        }

        return count;
    }
}

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