LeetCode 3041: Maximize Consecutive Elements in an Array After Modification Solution
Master LeetCode problem 3041 (Maximize Consecutive Elements in an Array After Modification), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3041. Maximize Consecutive Elements in an Array After Modification
Problem Explanation
Explanation:
To solve this problem, we need to find a way to maximize the number of consecutive elements in the array after allowing at most a one-unit increase in any element. We can achieve this by modifying the elements in the array in a way that allows us to select the maximum number of consecutive elements.
Here is the high-level algorithm:
- Sort the array
nums. - Iterate through the sorted array and for each element, check if increasing it by at most 1 would allow it to be part of a consecutive sequence.
- Keep track of the maximum number of consecutive elements found during the iteration.
Time complexity: O(n log n) - Sorting the array Space complexity: O(1) - Only using a constant amount of extra space
:
Solution Code
import java.util.Arrays;
class Solution {
public int maximizeConsecutive(int[] nums) {
Arrays.sort(nums);
int maxConsecutive = 0;
int consecutive = 0;
for (int num : nums) {
if (num > consecutive) {
consecutive = num;
maxConsecutive++;
}
}
return maxConsecutive;
}
}Try It Yourself
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