LeetCode 3046: Split the Array Solution

Master LeetCode problem 3046 (Split the Array), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3046. Split the Array

Easy

Array Hash Table Counting

Problem Explanation

Explanation

To solve this problem, we need to split the given array into two parts such that each part contains distinct elements. We can achieve this by iterating through the array and storing the frequency of each element in a HashMap. Then, we check if the size of the HashMap is equal to half the length of the array. If it is, we return true; otherwise, we return false.

Algorithm:
1. Create a HashMap to store the frequency of elements.
2. Iterate through the array and store the frequency of each element in the HashMap.
3. Check if the size of the HashMap is equal to half the length of the array.
4. If the size matches, return true; otherwise, return false.
Time Complexity: O(n) where n is the length of the input array.
Space Complexity: O(n) where n is the length of the input array.

Solution Code

import java.util.HashMap;

class Solution {
    public boolean splitArray(int[] nums) {
        HashMap<Integer, Integer> freqMap = new HashMap<>();
        
        for (int num : nums) {
            freqMap.put(num, freqMap.getOrDefault(num, 0) + 1);
        }
        
        return freqMap.size() == nums.length / 2;
    }
}

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